[sdiy] Re: Walsh Generator Release!!!

[Maciej Bartkowiak]

Magnus

> Fourier doesn't work on classic RLC stuff, but if you drop the R it
> works!

Alright, I was too generic. The response of RLC circuits is composed of
damped sines and cosines and in case of lossy circuit (any R!=0) is 
aperiodic, so Fourier series do not apply. What I wanted to say is that 
harmonic functions are invariables of RLC circuits, i.e. you can analyse 
those circuits by passing various sines and cosines through them (hence 
the concept of Fourier transmitance).

> You need LaPlace to handle the diminishing amplitude of an
> RLC. Fourier ONLY covers sine/cosine based waveforms. Given its
> period, the amplitude may not change for any of the periods. If it
> does (and it allways does BTW) then the Fourier theorem, transform
> etc. does not have the matematical guts to analyse it. This is a
> classic case of missapplying Fourier, which I keep raving about.
> It is sad to see that not too many people recognice and understand
> this fundamental flaw in many arguments.

This time you went too far. Fourier transform is perfect for analysis 
of nonperiodic functions. It may be not a good tool for analyisng
circuits,
but is an ideal tool for analyisng transient signals.

MB