[sdiy] inductors, B fields, and confusion
Scott E.
yahudinyhwh at sbcglobal.net
Sat Jun 12 19:56:53 CEST 2004
Hmmm... I think I'll just stick to 8 ohm drivers. :)
Scott E.
============================================================
Magnus Danielson wrote:
> rho
> 0 B²l²Sd²
> eff = ------ * --------
> 4*pi*c Re * Mm²
>
> Where rho0 is the density of the air.
>
> True, but there is another thing... are you really using the same gauge of
> wire?
>
> If we assume we have about the same cross-section area of copper wire on the
> coil (the coil thickness doesn't vary very much), then we would require a
> smaller gauge of wire. The resistance per meter of wire varies reciprocal to
> the wire radius in square, that is reciprocal to the per-wire-area.
>
> The cross-sectional of the coil will be the number of turns N times the
> effective area (there is some space inbetween the wires) so we have:
>
> A = N * A * geometry-factor
> tot Wire
>
> (The geometry factor handles the geometry-depending area-scaling which is due
> to the detailed packing geometry of the wires. It's a constant for our
> purposes. I'll assume it to be 1 for simplicity.)
>
> Now, there is a connection between N and l due to the geometry, a rought
> equalent would be:
>
> l = 2*pi*r*N
>
> where r is the effective radius of the coil wires as they are wound around the
> coil. r is assumed to be a constant for us as well.
>
> The wires area is found as
>
> 2
> A = pi*r
> wire wire
>
> Where rwire is the wires radius.
>
> The resistance Re is formed by
>
> rho * l rho*2*pi*r*N
> Re = ------- = ------------
> A A
> wire wire
>
> where rho is the resistivity constant for copper wire.
>
> It's just that N depends now on the Awire so:
>
> A
> tot
> N = -----
> A
> wire
>
> So
>
> rho*2*pi*r*A
> tot
> Re = ---------------
> 2
> A
> wire
>
> If we now stuff this into the efficient formula we have:
>
> l = 2*pi*r*N
>
>
> A
> tot
> N = -----
> A
> wire
>
> l = 2*pi*r*Atot/Awire
>
> rho rho 4*pi²*r²*A² A²
> 0 B²l²Sd² 0 B²Sd² tot wire
> eff = ------ * -------- = ------ * ----- * ------------- * ---------------
> 4*pi*c Re * Mm² 4*pi*c Mm² A² rho*2*pi*r*A
> wire tot
>
> this reduces down to
>
> rho 2*pi*r*A rho r*A
> 0 B²Sd² tot 0 B²Sd² tot
> eff = ------ * ----- * ----------- = ---- * ----- * ------
> 4*pi*c Mm² rho 2*c Mm² rho
>
> Now look at this formula. The things we can play with to change the resistance
> comes in the total area cross-section of the coil Atot, the radius of the coil
> r and the resistivity of the coil wire rho. The impedance we select to create
> is for all practical purposes an independent variable for the efficiency.
>
> Oh, and if anyone wonders, here is is the speed of sound in air and not the
> speed of light in vacuum. ;O)
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