50g

--- In 50g@yahoogroups.com, "Juan C." <jcbuchin@...> wrote:
>
> 
> 
> Hello there, I posted your second question in hp forums, and there 
is
> not an easy solution to that problem. Giancarlo Mattioni suggested 
this:
> 
> " If you don't mind, I'd point you to a comp.sys.hp48 thread (not 
that
> recent...):
> 
> 
> 
> 
> 
http://groups.google.com/group/comp.sys.hp48/browse_frm/thread/375e15
669\
> 9e66
> 
> 951/ebc3964b576b5bc1?hl=it&lnk=gst&q=whole+graph#ebc3964b576b5bc1
> 
> 
> 
> 
>  
> 
<http://groups.google.com/group/comp.sys.hp48/browse_frm/thread/375e1
566\
> 99e66951/ebc3964b576b5bc1?
hl=it&lnk=gst&q=whole+graph#ebc3964b576b5bc1>
> 
> In summary, the "other half" of the graph can't be showed as it 
is "made
> of" complex values for negative x values.
> 
> 
> 
> 
> I think you can catch the picture you want if you try to graph:
> 
> Y1(X)=|X^(5/3)|  "
> 
> 
> Thanks again. Much appreciated!
> 
> So I tried the IFTE function like this: IFTE(X>0,X^(5/3),-ABS(X^
(5/3))),
> it isn't an elegant solution but it works.
>