AVR-Chat

I think I understand what you are saying. I know pressure is equal on all sides. So as the ball desends in the water the point of Bouyancy would raise from the center of the ball. Would this cause it to rise faster at deaper depths?

Brian

--- In AVR-Chat@yahoogroups.com, Phil Birkelbach <phil@...> wrote:
>
> That is correct.  A cubic foot of water weighs considerably more than  
> 10 oz.  You could take that thing to the bottom of the Gulf and let it  
> go and it'll shoot straight back up.  This does assume that it doesn't  
> get crushed somewhere along the way.  Pressure does not matter.  The  
> assumption that pressure is only acting on the bottom is a bad one.   
> The pressure pushes up, down sideways and every direction all at  
> once.  The only pressure difference is the difference in the head  
> pressure of the water from the top of the object to the bottom of the  
> object and this is actually what causes it to be buoyant in the first  
> place.  This pressure difference is constant at all depths (Assuming  
> the density change of the water is negligible.  Which is a good  
> assumption at 15m but probably not at the bottom of the Gulf).  The  
> force pushing up on the object is the difference between the objects  
> weight and the weight of the fluid it displaces.  This is true of any  
> object in any fluid, including air.  Yes you are being lifted up by  
> the atmosphere, but you're just too darn heavy to notice.
> 
> Phil
>