AVR-Chat

It says that it MUST operate down to 4.80V. So, you should
be safe with a 5V supply. It says that it will work up to
130% of the rated power dissipation on the coil. Lets go
through the arithmatic:

Coil is 100 ohms. Rated voltage is 5V. Power is V * I  and
V = I * R so power can also be written V * V / R. The
numbers are then 5*5/100 = 25/100 = 0.25W.

130% of this is 0.325W. The coil resistance has not changed
so we can solve for voltage or 5.7V.

The coil current is one of the reasons your regulator is
getting warm. If the input voltage is 12 and the output is
5, the drop is 7V. 7V * 60ma = 420mW. That is almost a half
watt, just from the relay!

Jim


On Thu, 23 Sep 2004 16:43:10 -0700 (PDT)
 jay marante <jaythesis@yahoo.com> wrote:
> thanks guys...
>  
> attached here is the datasheet of the relay i used (6V).
> i don't think its possible to supply the coil with
> greater than 6V. or maybe i just misunderstood the
> datasheet.
>  
> i can't find a 5V relay in our local store so i have to
> live with that 6V relay. also, maybe the voltage
> regulator is alright. i'll try to reduce the input
> voltage.
>  
> thanks...
>  
> jay
> 
> 
> 
> 
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