Digital BW, The Print

--- In DigitalBlackandWhiteThePrint@y..., Todd Flashner <tflash@e...> 
wrote:
> on 9/26/01 3:17 PM, mh@t... wrote:
> 
> > He is saying a 10bit scan and a 14bit scan of the same thing will be
> > the same because 14bit scanners are capable of capturing more dense
> > negs and therefore the the scan will occupy the same space on the 16bit
> > histogram as with the 10bit scanner.
> 
> Come again please? I don't get this. They should look the same BECAUSE the
> 14 bit scanner is capable of capturing more dense negs?
> 
> Todd

A 14bit scanner captures (maps you could say) to a larger piece of the 
16bit histogram than the 10bit. But at the same time it captures more 
dense negs. So a scan of the same neg would use the same piece of the 
16bit histogram using both scanners. This is according to what Austin 
has been saying. I have no real world experience comparing this.
Does that make sense?

-mikeH