Digital BW, The Print

--- In DigitalBlackandWhiteThePrint@yahoogroups.com, "Anthony
Atkielski" <anthony@a...> wrote:
> Here's an example that might help:
> 
I disagree on one point :
The BW money machine collects all money, adding a few pennies
or dimes, loosing a five, whatever, according to its spectral
response.

The Color money machine collects the money in small change,
large change, and dollar bills.  But, disregarding its
similar spectral response gains or loss, there is no money
not accumulated.

The color filters are such that midway between the Red and
Green, their respective responses are down by 50%, but the
sum total of their light energy is still One.

Your coin analogy is an excellent way to represent a frequency
distribution, as long as the pennies are worth as much as the 
five dollar bills <laugh>

I think the real variant is the S curve amplitude non linearity
between films rather than the spectral domain..

Alex


> I have a machine that collects money.  It provides one total for all
coins,
> and one total for all bills.  I have another machine that also collects
> money, but it collects only quarters and five-dollar bills.
> 
> Using the first machine, I collect all the money I see around the house.
> The totals displayed by the machine are $8.25 and $21.  Based on these
> totals, I want to figure out what totals the second machine would have
> given, had I used it to collect the money.  Can you explain how I
would do
> this?
> 
> The money around the house represents the spectral distribution of
light in
> an original scene.  The first machine represents color film; the second
> machine represents B&W film.  Do you see the problem now?