Hi Ollie, > I see, you want to get an explicit expression of the phase- > frequency relation of your filter. > I doubt that you can derive this expression directly from the > transfer function of a filter. Yes you can, as I posted before: tan^-1 im(H(wj))/re(H(wj)). (Aaargh, I see I'm being forced into it!) - it is pretty nasty, here it is for the 5th stage o/p: tan^-1(-5*w + 3*k*w - 5*w^3 - k*w^3 + 14*w^5 + 22*w^7 + 7*w^9 - w^11)/ (1 + k - 7*w^2 - 3*k*w^2 - 22*w^4 - 14*w^6 + 5*w^8 + 5*w^10) So plug in frequency, w, and k (resonance), and get the phase back. [Mostly via Mathematica + time courtesy of not being able to get into work due to snow!] > To derive such a phase-frequency relation, one needs a formula > which relates the phase of the "incoming" frequency to the phase > of the "outgoing" frequency. This is given by the transfer function, see above! > So you could think of a system where a harmonic oscillator with <<snip lots of stuff I have no intention of trying to understand, as I don't see the relevance>> There are lots of good books out there on active filters if you want to learn more: _my_ particular favourite is 'Design of Analog Filters', Schaumann & van Valkenburg, OUP (Sorry everyone else for the algebra overload - especially Florian :-) - back to what you were doing!) Tim __________________________________________________________ Tim Stinchcombe Cheltenham, Glos, UK www.timstinchcombe.co.uk
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Re: question on a108 phase relationships
2010-01-13 by Tim
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