I'd say the math is wrong on both sides. :) IIRC, his drum is around 6.5" diameter, to achieve 20.48 inches circumference. He is generating 20480 bits per revolution, giving the 1000 bits per inch. The drum is rotating 6 times per second, so 6 * 20480 = 122880 bits per second. Somewhere in the earlier discussion, I think I saw that he is using 1 byte per bit (??? presumably to save the bit-shifting circuitry?), so that would work out to 122880 bytes/second. If he is using bit-shifting circuitry, so that each byte is 8 bits, then he can reduce that to 15360 bytes per second. Either way, it is a long way from 625000 bytes per second!! --- In Homebrew_PCBs@yahoogroups.com, "cunningfellow" <andrewm1973@...> wrote: > > > Joh Elson wrote: > > > > Note that my photoplotter as it is cranks > > out a pixel every 5 us, so even as 8-bit > > bytes, that is 625,000 bytes a second. > > 16.384" drum > 1000 dpi > 600 RPM (10 r/s) > 1 bit per pixel > 8 bits per byte > > I get 20 kilobyte per second > > Am I missing something >
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Re: Kodak PRD film ?
2011-03-06 by Andrew
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