the voltage at point B is actually +15v or 0v.
the opamp itself will spit out +15v or -15v depending on whether the
signal presented to the input is over the threshold set by the pot.
the diode and pulldown protect the 4015 from -15v and an open circuit
respectively.
</beginner>
the opamp itself will spit out +15v or -15v depending on whether the
signal presented to the input is over the threshold set by the pot.
the diode and pulldown protect the 4015 from -15v and an open circuit
respectively.
</beginner>
>Trying to learn more about this stuff...
>
>Here is a bit of the circuit from CGS13 (Gated Comparator) that I want
>to understand better:
>
>http://www.ph.k12.in.us/~drew/cgscomp.jpg
>
>At point "A", what is the possible range of voltage as the pot is
>swept? (I'm guessing -10v ~ +10v ?)
>
>Then assuming the input voltage (at the jack) range is 0v ~ 10v, what
>are the possible voltages at point "B" ? Are there just two possible
>conditions at "B", like 0v or +10v, or is there a whole range of
>possibilities at "B", depending on the pot setting and the input CV?
>
>I've been reading a bit about opamps but am *far* from comprehension
>yet...
>
>thanks:)
>Drew
