The PWM input is at zero volts with nothing connected. This gives a
square wave with nothing connected. If you put a 100K attenuator pot on
the PWM input, you could wire the normally closed lug on the CV input
jack to +12V with a 100K resistor. With nothing plugged into the jack
you would see approximately 0 to +4V as you sweep the pot. (12V *
(50K/150K)) That would give you a manual duty cycle adjustment when no
CV is plugged in. When you plug in a CV, the normal connection is
opened and pot attenuates the CV for PWM depth.
Richard
Jeff Laity wrote:
square wave with nothing connected. If you put a 100K attenuator pot on
the PWM input, you could wire the normally closed lug on the CV input
jack to +12V with a 100K resistor. With nothing plugged into the jack
you would see approximately 0 to +4V as you sweep the pot. (12V *
(50K/150K)) That would give you a manual duty cycle adjustment when no
CV is plugged in. When you plug in a CV, the normal connection is
opened and pot attenuates the CV for PWM depth.
Richard
Jeff Laity wrote:
> So if no voltage is applied to the PWM input, the squarewave duty
> cycle is 0% (non-functional), correct? Or is it 50%? If there's a way
> to get a vanilla 50% square out of the thing without using up more
> modules, that would be good enough.
>
> Could I rig up a circuit with a switch for manual PWM/CV PWM? Then tap
> the +VDC for a simple voltage through an attenuator for initial width
> if I'm not using PWM?
>