> From: steven > > I am wondering about what the mod lever on the polaris > actually does. it seems to engage the sweep (lfo) at the > rate that the sweep lever is set. but is its 'detination' > [to use a modern term] the filter cutoff---or filter > envelope? or what?? so then, it adds the sweep rate to the > filter--- at the 'level' set by the assignable control--- and > how does this differ from the 'vibrato' that also seems to be > adding this LFO at this single set rate? In arithmetic terms: pitch1 = key + transpose + lever2 * bend_lever_range + sweep * (osc1_vibrato * delay_envelope + lever1 * mod_lever_range) pitch2 = key + transpose + lever2 * bend_lever_range + sweep * (osc2_vibrato * delay_envelope + lever1 * mod_lever_range) So you can see that it applies vibrato to both oscillators equally, and has nothing to do with the filter. > I have other more > modern synths that allow you to assign the mod wheel to many > parameters--so im wondering what does this control do on the > polaris in 'modern' terms . I kinda wish it did more--or > could be modded to have more or more intense actions. it > seems to have a fairly limited scope compared to my other > synths. any comments/ explainations? There's also a less modern synth that lets you do this: the Chroma. -- Ciao, Paul D. DeRocco Paul mailto:pderocco@...
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RE: [chromapolaris] polaris MOD lever-- what does it really do? [in modern terms...]
2011-04-11 by Paul D. DeRocco
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