DbbBrook@... wrote: >Hi ya EVERY BODY. > >The equipment has been set up to compare the physical interactions of two >sound waves at different freq.: Two generators (A+B) are fed to both an >oscilloscope and a loud speaker via switch box enabling each to be viewed and >heard either separately or combined. > > >AMPLIFIER OSCILLOSCOPE A B > [ [ [ \ / > [ [ [_____________[ ] wall > [ [_________________________________[ ] (suppose to be box) > [__________________________// > // >( I tried to above to draw a diagram, to see if it would help any one better >- I know not very good, but at least I tried) WEEEEE! Don't give up my >studies for Art drawing HE HE > >DOES ANY ONE KNOW HOW TO WORK OUT THE CALCULATIONS FOR: > >The period output A as shown on the Oscillator is: 10 ms (milli seconds or >metres per seconds)? > >The period output B as shown on Oscillator is: 0.1ms > >I need to calculate the output freq. for each tone generator and the >resultant waveform of each sound wave at room temp? Output frquency in Hertz is the inverse of the period in Seconds. F= 1/period, if period is 0.1 ms then F=1/0.0001 = 10,000 Hz or 10 KHz I can only imagine that you need to graph the pressure wave if you are considering room temperature. I believe the velocity of sound is approx 320 Metres per second at 20 degrees C (no idea in imperial) in air. You may need to find a more accurate figure. In any case, Wavelength in Metres is equal to velocity/period. >0.1 ms I think is 0.010s? I know anything with nought on left from decimal >point. Oh I'm getting confused. Does any one know how to do this calculation? >If so can you explain it to me. 1 millisecond (mS) is one thousandth of a second or 0.001 seconds > >I am awaiting fro books to come through from book stores and libraries, but >need to do this formula by Wednesday. Hope I'm not helping you with your physics homework ;) S.
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Re: [L-OT] RE:of topic - ACOUSTICS AGAIN
2001-10-09 by Spectro
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