Lpc2000

Oops, after a closer look, your U1FDR and U1DLM/DLL settings
appear to be correct. Sorry about the confusion.

Bertrik

Bertrik Sikken wrote:
> I think the baudrate is incorrect.
> The divisor that you're using now does not make sense to me
> (looks like a bug in the baudrate calculation program).
> Try 78 for U1DLL (calculated from PCLK/(16*baudrate))
> and set U1FDR to 0.
> 
> Bertrik
> 
> dodge1955 wrote:
>> Bertrik and Guille,
>>
>> Here is my new code.  Still doesn't work right.  I've even tweaked the
>> MULVAL and DIVVAL numbers to better match the 12Mhz at 9600 baud.  It
>> doesn't come out perfect with a 12Mhz clock.  P0.8 blinks like mad,
>> but still no data out on 9600 PROCOMM.  PROCOMM works great directly
>> to my 9600 baud display.  But can't get it to work thru the 2148
>> chip's UART1.  Am I still missing something?
>>
>> Sutton - dodge55
>>
>> PINSEL0 |= 0x00010000;
>> PCONP |= 0x00000010;
>> U1FDR = 0x0000009A;          // MULVAL = 9, DIVVAL = 10
>> U1LCR = 0x83;                   // enable Divisor Latches
>> U1DLM = 0;
>> U1DLL = 0x25;                   // 9601.71 baud
>> U1LCR = 0x03;                // 8 bits, 1 stop, no parity, DLAB = 0
>> U1FCR = 1;
>> U1TER = 0x80;
>> U1IER = 0;
>>
>>
>>
>> void my_putchar(char c)
>> {
>>    if ((U1LSR & 0x20) != 0)      // TX buffer empty
>>    {
>>       U1THR = c;
>>    }
>> }
>>
>> void display_write(char text[])
>> {
>>    unsigned char i;
>>
>>    sprintf(display_output, "%s", text);
>>    for (i = 0; i < strlen(display_output); i++)
>>    {
>>       my_putchar(display_output[i]);
>>    }
>> }
>>
>>
>>
>>
>>
>>
>> --- In lpc2000@yahoogroups.com, "dodge1955" <sutton@...> wrote:
>>>
>>> I'm having a problem with getting UART1 to work on my Embedded Artists
>>> prototype board.  I have a serial display that has only 1 serial line.
>>>  In other words, you can only transmit to the display.  I can't get
>>> P0.8 (UART1 TX) to send any data.  Here is my setup at 9600.  And,
>>> another question is 'Do I really need an interrupt just to transmit?
>>> It seems like throwing a char out to U1THR should suffice.  It's
>>> probably something simple I'm missing.  Thanks.
>>>
>>> Sutton - dodge55
>>>
>>>
>>> VICIntSelect = 0;
>>> VICVectAddr2 = (unsigned int) uart1_out;
>>> VICVectCntl2 = 0x20 | 7;  // enables the UART1 interrupt, slot 7
>>> U1FDR = 0x00000010;   // MULVAL = 1, DIVVAL = 0
>>> U1DLM = 0;
>>> U1DLL = 0x48;      // 9600 baud
>>> U1LCR = 0x03;     // 8 bits, 1 stop, no parity, DLAB = 0
>>> U1FCR = 1;
>>> VICIntEnable |= 0x00000080;
>>>
>>> void display_write(char text[])
>>> {
>>>    unsigned char i;
>>>
>>>    sprintf(display_output, "%s", text);
>>>    for (i = 0; i < strlen(display_output); i++)
>>>    {
>>>       my_putchar(display_output[i]);
>>>    }
>>> }
>>>
>>> void my_putchar(char c)
>>> {
>>>    U1THR = c;
>>> }
>>>
>>> void uart1_out(void) __irq
>>> {
>>>    VICVectAddr = 0;
>>> }