I'll try it, thank you
--- In lpc2000@yahoogroups.com, Robert Adsett <subscriptions@...> wrote:
>
> At 01:12 PM 3/26/2006 +0000, grodo2k wrote:
> >Hello
> >I have a problem; the folowing code, allow to trigger an interrupt via
> >UART0 but when the interrupt occurs one time it doesn't end. When I
> >send a char from PC to the LPC I receive 'A' non stop. Can someone say
> >me, why?
> >
> >When I use the line: U0IIR_copy = U0IIR;, it ackts same.
> >The code:
> >
> >void UART0INT() __irq
> >{
> > if(toggle)
> > {
> > IO0CLR |= 0x20000; //clr P0.17
> > toggle = 0;
> > }
> > else
> > {
> > IO0SET |= 0x20000; //set P0.17
> > toggle = 1;
> > }
> > send_char_u0('A');
> > //exit ISR
> > //U0IIR_copy = U0IIR;
> > VICVectAddr = 0x00000000; //dummy write
> >}
>
> Read the section in the user manual on the IIR. Different interrupts
> sources require different acknowledgements. In particular the
receive data
> interrupt requires that data be read to acknowledge the interrupt.
Since
> you never read the data the interrupt is never acknowledged.
>
> You also need to enable the FIFO, although you are unlikely to see the
> effect of that until everything else is at least mostly working.
>
> Robert
>
> " 'Freedom' has no meaning of itself. There are always
restrictions, be
> they legal, genetic, or physical. If you don't believe me, try to
chew a
> radio signal. " -- Kelvin Throop, III
> http://www.aeolusdevelopment.com/
>Message
Re: Interrupts + Keil + LPC2294 again...
2006-03-27 by grodo2k
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