Brendan,
The information to the compiler is in the line:
ip = (int *)&buf[i];
Where it should be clear that the pointer is to an unaligned int.
Dave S.
--- In lpc2000@yahoogroups.com, "brendanmurphy37" <brendan.murphy@...>
wrote:
>
>
> When you say "I believe that the compiler has enough information to
> use byte aligned transfers", are you refering to the line:
>
> x[4] = *ip
>
> If so, why do you expect byte transfers? You're copying from one
> integer sized object to another. What happened before this line is
> irrelevant (in particular the fact that you've forced the "ip"
> pointer to have a badly alligned value).
>
> Or am I misunderstanding what you're asking?
>
> Brendan
>
> --- In lpc2000@yahoogroups.com, "dsidlauskas1" <dsidlauskas@>
> wrote:
> >
> > Consider the following code:
> >
> > ============================
> > char buf[]={1,2,3,4,5,6,7,8};
> > int *ip, x[4];
> >
> > for (i=0; i<4; i++)
> > {
> > ip = (int *)&buf[i];
> > x[4] = *ip;
> > }
> > =============================
> > The Keil compiler compiles this without warning, but does not
> produce
> > the expected (for me) result in x. The problem is that Keil uses the
> > LDR instruction to effect the transfer and this is valid only on 4
> > byte boundaries.
> >
> > GCC compiles but does give a non-aligned access warning.
> >
> > I believe that the compiler has enough information to use byte
> aligned
> > transfers, and should, or at least give a warning.
> >
> > Anybody want to weigh in on this one.
> >
> > Thanks in advance for your comments.
> >
> > Dave Sidlauskas
> >
>Message
Re: For C Experts
2006-03-30 by dsidlauskas1
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