Lpc2000

Dave,

If I understand you (now more correctly): because byte packing is
default, you want a vanilla cast (without __packed prefix) to be
treated as byte packed cast.

How would a programmer then indicate a cast to a vanilla (not packed)
pointer?

If the compiler always assumes byte packed no matter what, arguably
the compiler cannot take advantage of the faster method of dealing
with composite objects.

Jaya

--- In lpc2000@yahoogroups.com, "dsidlauskas1" <dsidlauskas@...> wrote:
>
> Jaya,
> 
> I don't think I'm asking it to connect the two statements.
> 
> What I'm expecting it to do is to recognize that buf is a byte packed
> object (the defalt for the compler)and when casting byte packed
> objects the compiler should cast them to other byte packed objects.
> 
> in otherwords;
> 
> char buf[10];
> int ip*;
> 
> ip = (int *)&buf[5];
> 
> should be treated by the compiler as:
> 
> ip = (__packed int *)&buf[5];
> 
> and this is because char buf[10] is a byte packed object for this
> compiler.
> 
> Dave