Lpc2000

Thanks for the help guys.  I finally got things working and  ultimately George was right in that I inited some of the UART0  parameters wrong.  In addition to initing the UART0 for 19200 and  setting Hyperterminal to 9600, I selected UART1 in the pinselect0  register, no UART0.
  
  - John

"George M. Gallant, Jr." <ggallant571@...> wrote:        John,
  
  Without looking in detail, your narrative say setting hyperterm to 9600
  and the code comment says 19200.
  
  George
  
  On Mon, 2006-04-24 at 10:49 +0000, jstamos111 wrote:
  
  > Hey all,
  > 
  > I am trying to get UART0 output to display on hyperterminal for a 
  > board I made based on the LPC2106 processor.  I use the ISP and 
  > UART0 to program the board with Philips flash utility, then start 
  > hyperterminal with the following settings: 9600 bits/second, 8 
  > databits, no parity, 1 stop bit, and no flow control.  I set 
  > hyperterminal to listen on the same com port as the one I used to 
  > program the flash memory.  I also have the computer's com port 
  > connected to the LPC2106's same UART (UART0?) that I used to program 
  > the flash memory.  Finally, I hit reset, but the output is not 
  > displayed in hyperterminal.
  > 
  > Any thoughts on why I am not seeing any output in hyperterminal?
  > 
  > Here is my code which I compiled uvision by keil tools.  I pretty 
  > much stole this code from hitex's book for the philips LPC 
  > processors.
  > 
  > void UART0 (void)      
  > {
  > PINSEL0 = 0x05;       // Select TxD and RxD on pin connect block
  > U0LCR = 0x80;            //Enable programming of divisor latches
  > 
  > U0DLL = 0xC2;            //Program the divisor latch for 19200 baud
  > U0DLM = 0x00;
  > 
  > U0LCR = 0x33;            //Program the line control 8\N\1
  > U0FCR = 0x4F;            //enable the FIFO's
  >                   
  > }
  > 
  > int main() {
  >       UART0();
  > 
  >       printf("Hello World\n"); //Call the printf function
  >         while(1) {}
  >         return 0;
  > }
  > 
  > Much Thanks.
  > - John
  > 
  > 
  > 
  > 
  > 
  > 
  > 
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