Lpc2000

--- In lpc2000@yahoogroups.com, Jan Thogersen <jan@...> wrote:

>        E3A0220E   mov r2, #0xE0000000
>        E2822901   add r2, r2, #0x00004000
>        E2822018   add r2, r2, #0x00000018
...
> How come it takes 3 instruction to load the correct address into r2. 

My guess is that you are generating 16-bit code with and compiler is
minimising code size.  The above three instructions then would occupy
three 16-bit locations in memory, while the replacement
 
>        ldr r2 #e0004018

would require one 32-bit instruction and another 32-bit to store the
constant.

Jaya