Lpc2000

You don´t need to do that way using IOCLR and IOSET. Try the following:

 for(;;)
 {    
   IO1SET = (1 << 25);	// This set pin P1.25 only, and leaves other pins unchanged
   IO1CLR = (1 << 25);	// This clear pin P1.25 only, and leaves other pins unchanged
 }


If you are using the new lpc 2000 series ( such lpc214x, lpc213x or lpc2103 ), you can test using FIOSETx and FIOCLR. Check the chapter "General Purpose Input/Output ports (GPIO)" in the respective user manual.

Good luck!

German

ocnek1 wrotte:
> Hello,
>
> I wrote this little test to see how fast I could toggle an IO pin. 
> Using the way I did it here from rising edge to falling edge the time
> is only ~540nS.  This seems slow to me.  Is it?  I have verified that
> the DesiredSpeed is indeed locked at ~60MHz
>
> Thanks,
> Oc.
>
>
> int main( void)
> { 
>   IO1DIR |= (1 << 25); 
>
>   (void)SetNativeSpeed(14746uL);	
>   (void)SetDesiredSpeed(60000uL);	
>
>   (void)SetMAM( 3u, MAM_full_enable);
>   (void)VPBControl(VPB_DIV1);		
>     
>  
>   
>  for(;;)
>  {    
>    IO1CLR &= ~(1 << 25);
>    IO1SET |= (1 << 25);
>      
>    IO1CLR |=  (1 << 25);
>    IO1SET &= ~(1 << 25);	
>  }
>
>
> }
>
>
>
>
>
>
>
>  
> Yahoo! Groups Links
>
>
>
>  
>
>
>
>
>   


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