Lpc2000

If you are using input capture interrupt, and using more than one 
channel on the timer module, be sure to check item Timer.1 on latest 
errata sheet.


--- In lpc2000@yahoogroups.com, "bpesun" <bpesun@y...> wrote:
> 
> I am using 2114,and I want to use input capture to measure the 
pusle.
> but i can't into the interrupt.DOes any people have done that?Can i 
> see your code?
> the following is my code,but it can/t go to interrupt.
> /******************************************
> * Ãû³Æ    :  void Timer_Init(void)
> * ¹¦ÄÜÃèÊö:  ¶¨Ê±Æ÷0ÖжϷþÎñ³ÌÐò
> * ÊäÈë²ÎÁ¿:  ÎÞ
> * Êä³ö²ÎÁ¿:  ÎÞ
> * µ÷ÓÃ×Ó³Ì:  ÎÞ
> * ʹÓ÷½·¨:
> --------------¡ª*/
> void __irq  IRQ_Timer1(void)
> {                                      
>    Prints("int");//this is my debug function
>    if( (IO0SET&LEDCON) == 0 ) IO0SET = LEDCON;	
>       else  IO0CLR = LEDCON;    		 	            
> 	     
>    T1IR = 0x02;	    		
> 	                      // Çå³ýÖжϱêÖ¾
>    VICVectAddr = 0x00;			
> 	                  // ֪ͨVICÖжϴ¦Àí½áÊø
> }
> 
> 
> 
> void  Timer1Init(void)
> {     
>    T1PR = 99;			    		
>    T1CCR |= (1<<9);           
>    T1CCR |= (1<<10);            //cap1.3ÉÏϽµÑØÌø±ä½«TCÄÚÈÝ×°ÈëCR3
>    T1CCR |= (1<<11);            //cap1.3Éϲ¶»ñ×°ÔزúÉúÖжÏ
>    T1IR|=0x80;                     //Çå³ýÖжϱêÖ¾
>    T1TCR = 0x03;		   			
> 	       T1TCR = 0x01; 
>    
>    VICIntSelect = 0x00000000;				
> 		
>    VICVectCntl0 = 0x20|5;				
>   VICVectAddr0 = (uint32)IRQ_Timer0; 		        
> 
>    ICIntEnable = (1<<5);				   
>    PINSEL1|=(1<<10);                
>    PINSEL1|=(1<<11);                //    
> 
> }