Sorry guys. Guess I should have checked the Errata first.
Changing the standard UART0 code from (a) to (b) sorted it.
(a)
static unsigned int
peripheralClockFrequency(void)
{
unsigned int divider;
switch (VPBDIV & 3)
{
case 0:
divider = 4;
break;
case 1:
divider = 1;
break;
case 2:
divider = 2;
break;
}
return processorClockFrequency() / divider;
}
(b)
static unsigned int
peripheralClockFrequency(void)
{
unsigned int divider;
unsigned int vpbdivtemp;
vpbdivtemp = VPBDIV;
vpbdivtemp = VPBDIV;
switch (vpbdivtemp & 3)
{
case 0:
divider = 4;
break;
case 1:
divider = 1;
break;
case 2:
divider = 2;
break;
}
return processorClockFrequency() / divider;
}
/******************************************************************/
There are 10 kinds of people: those who understand binary and those
who don't.
/******************************************************************/
--- In lpc2000@yahoogroups.com, Adam Wilkinson <lpc2129@y...> wrote:
> Love the LPC2129.
>
> Can anyone explain why the following line of code is
changing/resetting VPBDIV from 0x01 to 0x00??
>
> IO0DIR = 0x006F0001;
>
> Prior to this line IO0DIR is set to 0x006FFF01;
>
> ?? Thanks ??
>
>
> Send instant messages to your online friends
http://uk.messenger.yahoo.com
>
> [Non-text portions of this message have been removed]Message
Re: IO0DIR changing VPBDIV ??
2005-04-01 by Adam and Simon
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