Lpc2000

Hi

I use I2c with interrupt and it's work fine

example of my code in new0001.c

jean-baptiste

>>> anotheruglygeek@... 24/08/04 17:40:16 >>>
I am having problems getting the I2C interrupt to work.  I have setup 
the VIC to enable the I2C interrupt (channel 9) in exactly the same 
way I have setup all the other interrupts (which work).

I can see that the SI bit is getting set correctly - and I can use 
the I2C interface by polling this - but the ISR is not executing.  

Does the I2C interrupt have to be enabled anywhere else or is setting 
up the VIC enough?  The UART requires an enable bit to be set also 
but I cannot find an equivalent for I2C.

The samples in the files section seem to also use polling.  Any help 
appreciated.

Thanks!


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[Non-text portions of this message have been removed]

Hi,

Thanks for the info - where can I get a copy of the source file?  I 
have looked in the files section but cannot see it.

Regards.

--- In lpc2000@yahoogroups.com, "Jean-Baptiste Houdry" <jean-
baptiste.houdry@s...> wrote:
> Hi
> 
> I use I2c with interrupt and it's work fine
> 
> example of my code in new0001.c
> 
> jean-baptiste
> 
> >>> anotheruglygeek@y... 24/08/04 17:40:16 >>>
> I am having problems getting the I2C interrupt to work.  I have 
setup 
> the VIC to enable the I2C interrupt (channel 9) in exactly the same 
> way I have setup all the other interrupts (which work).
> 
> I can see that the SI bit is getting set correctly - and I can use 
> the I2C interface by polling this - but the ISR is not executing.  
> 
> Does the I2C interrupt have to be enabled anywhere else or is 
setting 
> up the VIC enough?  The UART requires an enable bit to be set also 
> but I cannot find an equivalent for I2C.
> 
> The samples in the files section seem to also use polling.  Any 
help 
> appreciated.
> 
> Thanks!
> 
> 
> Yahoo! Groups SponsorADVERTISEMENT
> 
> Yahoo! Groups Links
> To visit your group on the web, go to:
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>   To unsubscribe from this group, send an email to:
> lpc2000-unsubscribe@yahoogroups.com 
>   Your use of Yahoo! Groups is subject to the Yahoo! Terms of 
Service. 

> 
> 
> 
> [Non-text portions of this message have been removed]