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Buchla VS. Wiard

Buchla VS. Wiard

2001-10-11 by mark verbos

Hi,

In a previous post, Grant casually mentioned that the control voltage
section in the Borg is exponential and the Buchla lopass gate is linear.
I don't really understand. I thought that the exponential behavior came
from the Vactrol itself. Is that why the Buchla has that Zener? So there
is a break point in a linear curve? So the transistor method like the
Korg MS-20 VCA is more of a true "curve".

I always wondered what the difference was between these two. And the
different ones that Don used.

--
mark verbos

"if you want something done right, build it yourself."

www.simple-answer.com

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on my label SIMPLE ANSWER "Form is Emptiness" Simple Answer 006 out now,
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Re: Buchla VS. Wiard

2001-10-11 by grantrichter2001@yahoo.com

> section in the Borg is exponential and the Buchla lopass gate 
is linear.
> I don't really understand. I thought that the exponential behavior 
came
> from the Vactrol itself. Is that why the Buchla has that Zener? 
So there
> is a break point in a linear curve? 

Hi Mark,

This is what I have been dealing with in the Woggle Bug (same 
Vactrol control circuit). The Zener does produce a breakpoint so 
there is a two section curve. The problem was that the original 
circuit did not work well with Joysticks. Since the Joy Rider was 
one of the goals, I went with a traditional expo converter for the 
Borg which gives a very nice feel when controlled by a joystick. In 
the original circuit, all the action was bunched up at the top end. 

Also, I don't want to reissue the Buchla circuits. So you can say 
the Borg sounds more like a Buchla than anything else 
available, but is still unique - not a copy.

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