[sdiy] Since it's 9/09, it's time for more 909 questions :)

TooManySynths p8051 at yahoo.com
Mon Sep 10 00:26:20 CEST 2001


> > One more question:

I lied, sorry, one more...

> No.
> The trigger pulse switches on Q1, Q1 conducts and
> pulls down the base of Q5
> lower than it's emitter via D5 and R34. This
> switches Q5 on and allows the
> accent cv to charge C12 for env2. This happens at
> the leading edge of the
> trigger pulse.
> The trigger pulse is inverted at the output of Q1.
> The inverted pulse is
> inverted again by Q2 which charges C7 via D6.
> The triggers at D5 and D6 are opposite senses. The
> non-inverted trigger at
> D6 is inverted again by Q3 before it reaches the
> base of Q4 - which then
> works in the same way as Q5 (with the difference
> that C7 and Q3 stretch the
> pulse length, and give it a slight downward slope).
> It takes a negative pulse relative to the emitters
> to switch on Q4 and Q5
> (PNP).

Ok, that makes sense.  I cannot tell if the cathode of
D6 is connected to the collector of Q4.  If it is not,
however, then I cannot see how C7 will affect the
envelope if the Accent CV is at 0v.

Am I missing something else?

Thanks 
Daryl



__________________________________________________
Do You Yahoo!?
Get email alerts & NEW webcam video instant messaging with Yahoo! Messenger
http://im.yahoo.com



More information about the Synth-diy mailing list