Hi Cobb, I probably didn't explain myself too well, plus my typo where I said I wanted 3V from the converter, I really meant 5V. I have 4 batteries (this is the maximum room I have in my case). The printer runs from 5V and consumes 3.5A peak. The idea was to connect 2 pairs in series to give 3V, and then connect the 2 x 3V cells in parallel to double the capacity. As this is a hand held device I do not want to connect all 4 in series and use a regulator to bring it down to 5V, thats a waste of power as I want maximum operating time from the device. Others have raised the issue of internal resistance which I had not considered, and suggest NiMh batteries which would mean I would have only 2.4V max to boost to 5V. Cheers Col --- In AVR-Chat@yahoogroups.com, "Cobb, Quentin" <quentin_cobb@t...> wrote: > I don't get it. You have four AA batteries, so you have 5v if you run them > in series. You want 5v to run the printer. Why do you need to convert > anything? > > > > > > -----Original Message----- > From: C Sizer [mailto:aussiecol39@y...] > Sent: July 30, 2004 8:17 AM > To: AVR-Chat@yahoogroups.com > Subject: [AVR-Chat] DC-DC converter > > > Hi guys, > > I am designing a university project, a hand-held printer using the > AVR and a small thermal printer. For portability I want to use 4 x > 2300mAh AA batteries in serial/parallel to provide me with 3V. > > The printer runs on 5V but consumes over 3.5A peak, so I require a DC- > DC converter circuit (or at least a starting point) to provide 3V at > 5A peak. > > Has anyone designed anything like this, or can give me some advice? > Maybe someone has an idea for a better battery for me to use? > > Cheers > Col > > > > > > Yahoo! Groups Links > > > > > > > - Scanned for viruses by MessageLabs on behalf of Tesco Corporation - > > - Scanned for viruses by MessageLabs on behalf of Tesco Corporation -
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Re: DC-DC converter
2004-07-31 by C Sizer
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