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Thread

making a simple battery pack?

making a simple battery pack?

2005-10-25 by rgmccaig

If I took 2 9v batteries in series to create 18V, plus a resistor in
series to lower the voltage, could I plug that in to run my Evo?

I am thinking the load of the Evolver is 15V / 0.5 A = 30 ohms?

So a 10 ohm resistor in series with the evolver would take 1/4 of the
18V, ie 4.5 V, leaving 13.5V for the Evo.

Anybody know if I'm thinking about it the right way?

Re: making a simple battery pack?

2005-10-25 by Jonathan Villegas

Hello,

The thinking is not right.

Putting a resistor in series with your batteries just
throttles the current flow.

The Evo (desktop) needs about 750 mA of current at
13.6 VDC (output rating of wall-wart). Nine-volt
batteries aren't capable of supplying 3/4 of an Amp of
current. If it works at all, it will be for a very
short time.

You might want to research battery packs (of the
appropriate voltage) used by camcorders or
photographers. This may be a better solution for
battery operation.

~ Jonathan
www.lbop.net


--- DSI_Evolver@yahoogroups.com wrote:

Message: 3         
   Date: Tue, 25 Oct 2005 00:14:21 -0000
Show quoted textHide quoted text
   From: "rgmccaig" <rgmccaig@...>
Subject: making a simple battery pack?

If I took 2 9v batteries in series to create 18V, plus
a resistor in
series to lower the voltage, could I plug that in to
run my Evo?

I am thinking the load of the Evolver is 15V / 0.5 A =
30 ohms?

So a 10 ohm resistor in series with the evolver would
take 1/4 of the
18V, ie 4.5 V, leaving 13.5V for the Evo.

Anybody know if I'm thinking about it the right way?


		
__________________________________ 
Yahoo! FareChase: Search multiple travel sites in one click.
http://farechase.yahoo.com

Re: making a simple battery pack?

2005-10-25 by matsag21

Hello,

there is a thread on the subject in the evolver board.
here is the link:
http://www.ex5tech.com/ex5ubb_cgi/ultimatebb.cgi?ubb=get_topic&f=23&t=000148

let us know how it goes!

cheers

Mathieu


--- In DSI_Evolver@yahoogroups.com, Jonathan Villegas
<jville.geo@y...> wrote:
Show quoted textHide quoted text
>
> Hello,
> 
> The thinking is not right.
> 
> Putting a resistor in series with your batteries just
> throttles the current flow.
> 
> The Evo (desktop) needs about 750 mA of current at
> 13.6 VDC (output rating of wall-wart). Nine-volt
> batteries aren't capable of supplying 3/4 of an Amp of
> current. If it works at all, it will be for a very
> short time.
> 
> You might want to research battery packs (of the
> appropriate voltage) used by camcorders or
> photographers. This may be a better solution for
> battery operation.
> 
> ~ Jonathan
> www.lbop.net
> 
> 
> --- DSI_Evolver@yahoogroups.com wrote:
> 
> Message: 3         
>    Date: Tue, 25 Oct 2005 00:14:21 -0000
>    From: "rgmccaig" <rgmccaig@i...>
> Subject: making a simple battery pack?
> 
> If I took 2 9v batteries in series to create 18V, plus
> a resistor in
> series to lower the voltage, could I plug that in to
> run my Evo?
> 
> I am thinking the load of the Evolver is 15V / 0.5 A =
> 30 ohms?
> 
> So a 10 ohm resistor in series with the evolver would
> take 1/4 of the
> 18V, ie 4.5 V, leaving 13.5V for the Evo.
> 
> Anybody know if I'm thinking about it the right way?
> 
> 
> 		
> __________________________________ 
> Yahoo! FareChase: Search multiple travel sites in one click.
> http://farechase.yahoo.com
>

Re: making a simple battery pack?

2005-10-25 by rgmccaig

Thanks to you both.. Guess I'm off to find an RC battery as mentioned
in the other thread.

I understand my mistake about the current limit; I forgot to wonder
how much current a 9v could supply.

I'm still curious, if you have a given battery you must work with, and
you want to reduce the voltage you are delivering, what is the best
way to do that (rather than a resistor in series)?

cheers


--- In DSI_Evolver@yahoogroups.com, "matsig21" <mathieu@t...> wrote:
>
> Hello,
> 
> there is a thread on the subject in the evolver board.
> here is the link:
>
http://www.ex5tech.com/ex5ubb_cgi/ultimatebb.cgi?ubb=get_topic&f=23&t=000148
Show quoted textHide quoted text
> 
> let us know how it goes!
> 
> cheers
> 
> Mathieu
> 
> 
> --- In DSI_Evolver@yahoogroups.com, Jonathan Villegas
> <jville.geo@y...> wrote:
> >
> > Hello,
> > 
> > The thinking is not right.
> > 
> > Putting a resistor in series with your batteries just
> > throttles the current flow.
> > 
> > The Evo (desktop) needs about 750 mA of current at
> > 13.6 VDC (output rating of wall-wart). Nine-volt
> > batteries aren't capable of supplying 3/4 of an Amp of
> > current. If it works at all, it will be for a very
> > short time.
> > 
> > You might want to research battery packs (of the
> > appropriate voltage) used by camcorders or
> > photographers. This may be a better solution for
> > battery operation.
> > 
> > ~ Jonathan
> > www.lbop.net
> > 
> > 
> > --- DSI_Evolver@yahoogroups.com wrote:
> > 
> > Message: 3         
> >    Date: Tue, 25 Oct 2005 00:14:21 -0000
> >    From: "rgmccaig" <rgmccaig@i...>
> > Subject: making a simple battery pack?
> > 
> > If I took 2 9v batteries in series to create 18V, plus
> > a resistor in
> > series to lower the voltage, could I plug that in to
> > run my Evo?
> > 
> > I am thinking the load of the Evolver is 15V / 0.5 A =
> > 30 ohms?
> > 
> > So a 10 ohm resistor in series with the evolver would
> > take 1/4 of the
> > 18V, ie 4.5 V, leaving 13.5V for the Evo.
> > 
> > Anybody know if I'm thinking about it the right way?
> > 
> > 
> > 		
> > __________________________________ 
> > Yahoo! FareChase: Search multiple travel sites in one click.
> > http://farechase.yahoo.com
> >
>

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