Yamaha DTXpress/DTXplorer/DTXtreme

Wow, that's a quick service! Thanks a lot! 

I understand the circuit. One more thing: 
Suppose I would want to add an extra pad signal to a stero pad signal. Then, I guess one 
should 
- take J3 from the stereo pad (main = ingoing tip), with D2  to outgoing tip
-  take J1 from the stereo pad (rim = ingoing ring) and omit the circuit 'behind' J1 except 
perhaps D1, then directly to outgoing ring (if there is a signal on J1, then J3 also already 
has a signal since it's coming from the stereo pad) 
- take J4 from extra mono pad, include the circuit (top part with extra 10k) and add 
signals to outgoing rim and tip as 'usual'. 

Does that make sense? Do I pass the DIY electronics test? ;)
Thanks again!

Erik
 


--- In DTXpress@yahoogroups.com, "Keith" <keith@k...> wrote:
>
> --- In DTXpress@yahoogroups.com, "epvk_jahoe" <yahoo@e...> wrote:
> >
> > Hi,
> > 
> > I'm thinking about making a dtxpander circuit for a brain inputs 6
> and 7, by connecting a  
> > trigger to the stero PCY65S's. Some time ago, Keith wrote that just
> a few extra 
> > components are necessary to do just that, but the problem is I don't
> know how the 3 
> > different signals ("rim1", "rim2", main) can run through a stereo (2
> signal) cable (similarly, 
> > how this works for the TP65S in input 2 is a puzzle). 
> 
> Erik,
> 
> The piezo signal always goes to the tip of the connector.  The ring is
> connected to the rim FSR.  To get two rim shots, a 10k ohm resistor is
> in series with the second rim FSR.  This allows the DTXpress to detect
> which rim was hit.  
> 
> You can do the same with the DTXpander - i.e. connect three pads to
> one input.  I will post a modified circuit to show how you would do
> that.  Basically you need two transistor circuit with a 10k resistor
> in series with one.  They will both then drive the conector ring, but
> being "open collector" there is no clash of signals.
> 
> Keith.
>