--- In DigitalBlackandWhiteThePrint@yahoogroups.com, "Paul D. DeRocco" <pderocco@i...> wrote: > > From: Roy Harrington .. > > I think you are confusing dynamic range with smoothness or > > resolution of gray > > values thoughout the scale. Dynamic range is only a measure of > > how far apart > > the darks shadows can be from the brightest highlights. It's a > > matter of seeing > > detail in shadows without blowing out the highlights. Dynamic > > range is just > > a ratio -- no more. > > Sure, but the dark end isn't limited by the numeric range--that goes to > zero, and you can't divide by zero. It's limited by the noise level, which > means that photographing the inside of your lens cap will give you nonzero > output. The average of that noise defines your black level. > ... > -- > > Ciao, Paul D. DeRocco > Paul mailto:pderocco@i... But the "min" in the denominator isn't the smallest integer number that may come out of the A/D. The min is the minimum signal that produces an output larger than the output you see from just noise. Maybe this example will illustrate what I mean: Let's assume we calibrate the A/D such that it reachs beyond the voltages output by the sensor. Say its a 10bit A/D so the possible outputs are 0 to 1023 but the noise level with no signal input reads out 20, and the max read out you get is say 1000 -- the clipping point. What is the dynamic range? It's the ratio of the signal input values (i.e. light levels) that produce the clip point =1000 over the input that produces the smallest signal value = 21. Because of the linearity of input signal with the digital output the ratio is: dynamic range = ( 1000-20 )/ (21-20) = 980/1 or 980-to-1. The dark end is very much the limiting area. Note that 21 is the first signal and 22 is the second signal. But the signals involved here are: (22-20) = 2 and (21-20) = 1. The second detectable signal must be twice the size -- a full stop brighter. To get to just 36 output you need 4 stops brighter. You need to be much larger than the noise level to produce decent separation of grays. That's you need a much larger DynRg in say a scanner that it seems you ever use. Roy
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Re: Artifacts with Digital images
2005-07-04 by Roy Harrington
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