Ah, sorry, I didn't really read the details. Sounds like he should be able to fix it by soldering high value resistors to the inputs of the MFB EG... I think. On Sun, Nov 15, 2009 at 3:49 PM, Synthomaniac <tony.steventon@talk21.com>wrote: > > > Hi Guys > > There seems to be some confusion about what's going on with loading, volts, > current etc. The good news is that Ohm's Law isn't about to be disproved > anytime soon. Volts and current are linked in Ohm's law by resistance, in > this case the output resistance of the SH101 - this is about 22k and it > connects to +15V in the SH101 gate out circuit. > > The MFB EG acts as a load and two in parallel act as a greater load, i.e. > more current will flow. If for argument's sake the MFB has an input > resistance of 10k then two EGs in parallel would then give a load of 5k. > I'll ignore the A140 since that that has a very high input resistance (mine > are around 5M to 7M). > > The arithmetic for this example is that 15V is loaded by 22k out plus a 5k > load = 27k. This acts as a potential divider thus 15/27 x 5 = 2.8V. Not very > big! So the more current out the more the voltage drop across the output > resistance and hence a smaller gate voltage. So yes it needs a buffer to > isolate the SH101 output's high output resistance; I use an A185-1. If you > just had A140s then these have such a high resistance that it shouldn't make > any difference. > > Hope that helps clear up the mystery. > I'd be inteested if anyone can tell me what the MFB EG input resistance > actually is. > > Cheers > Tony > > > --- In Doepfer_a100@yahoogroups.com <Doepfer_a100%40yahoogroups.com>, > Monroe Eskew <monroe.eskew@...> wrote: > > > > Pardon if this is a dumb question, but are you sure you're measuring > voltage > > and not power? Is Ohm's law really that blatantly false? I've noticed > VCOs > > don't respond to voltage only; they are influenced by the amperage as > well. > > > > On Sun, Nov 15, 2009 at 2:43 PM, Computer Controlled <acidted@...>wrote: > > > > > > > > > > > > That's why there are Buffered Multiples, passive ones drop the voltage > > > levels. So they need to be buffered to keep them at original levels. > > > > > > I just didn't think that the level would drop by so much! > > > > > > > > > Monroe Eskew wrote: > > > > It's strange because in theory the voltage should not drop since > these > > > are > > > > parallel circuits-- only the current should change. > > > > > > > > On Sun, Nov 15, 2009 at 2:16 PM, Computer Controlled <acidted@ > ...<acidted%40gmail.com> > > > > >wrote: > > > > > > > > > > > >> I've noticed recently that the A-180 Multiple really cuts the > voltage > > > >> signal down quite substantially. I just got an MFB Dual ADSR and > noticed > > > >> that when i mult the Gate Output of my SH-101 by 3x, it drops the > gate > > > >> voltage down to where the MFB won't trigger anymore. Basically, i > had it > > > >> set up where the gate out went into the A-180, then the first 2 outs > > > >> went to the two Gate Ins on the MFB and the 3rd out went to my A-140 > EG. > > > >> If i pulled the cable out that went to the A-140, the MFB would > fire, > > > >> but not with it inserted. However, it works if i use my 303, which > has a > > > >> hotter Gate signal. I checked the gate out voltages coming of the > 101 > > > >> direct, then at each output of the A-180. I got the following: > > > >> > > > >> Direct Out from 101: 11.56v > > > >> Into the A-180 w/no other cables inserted: same as above > > > >> with 2 cables inserted: 7v > > > >> with 3 cables inserted: 5.5v > > > >> > > > >> This is quite a bit of voltage drop if you ask me. Is there anyway > to > > > >> mod the A-180 so it doesn't eat up all my voltages? > > > >> > > > >> -Larry > > > >> > > > >> > > > >> > > > > > > > > > > > > [Non-text portions of this message have been removed] > > > > > > > > > > > > > > > > ------------------------------------ > > > > > > > > Yahoo! Groups Links > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > [Non-text portions of this message have been removed] > > > > > [Non-text portions of this message have been removed]
Message
Re: [Doepfer_a100] Re: A-180
2009-11-16 by Monroe Eskew
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