Hello. I am doing a series on the A106-5. I read that the CV2 is a polarized input so around 12 o' clock the cv input is at zero, at +5 it is at fully positive input, and at -5 it is an inverted version of the cv input.
As long as I understand this correctly, at zero I should have no cv but when I input an envelope it does affect the cutoff a slight amount.
Can anyone confirm this behavior or explain if I am misunderstanding something?
Thanks for any help.
Raul