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Doepfer A106-5 filter CV2 question

Doepfer A106-5 filter CV2 question

2015-02-05 by raulpena1974@yahoo.com

Hello. I am doing a series on the A106-5. I read that the CV2 is a polarized input so around 12 o' clock the cv input is at zero, at +5 it is at fully positive input, and at -5 it is an inverted version of the cv input.

As long as I understand this correctly, at zero I should have no cv but when I input an envelope it does affect the cutoff a slight amount.

Can anyone confirm this behavior or explain if I am misunderstanding something?


Thanks for any help.


Raul

Re: [Doepfer_a100] Doepfer A106-5 filter CV2 question

2015-02-05 by Neil Kagan

If it's like the A-133, I find the 'zero' point to be very small. Same with the Polarizing mixer.

Neil

Sent from my iPhone
Show quoted textHide quoted text
> On 5 Feb 2015, at 03:14, raulpena1974@yahoo.com [Doepfer_a100] <Doepfer_a100@yahoogroups.com> wrote:
> 
> Hello. I am doing a series on the A106-5. I read that the CV2 is a polarized input so around 12 o' clock the cv input is at zero, at +5 it is at fully positive input, and at -5 it is an inverted version of the cv input.
> 
> As long as I understand this correctly, at zero I should have no cv but when I input an envelope it does affect the cutoff a slight amount.
> 
> Can anyone confirm this behavior or explain if I am misunderstanding something?
> 
> 
> 
> Thanks for any help.
> 
> 
> 
> Raul
> 
>

Re: [Doepfer_a100] Doepfer A106-5 filter CV2 question

2015-02-05 by Martin Fay

Dieter, is the A-133 implemented with "back-to-back" VCAs? If so a  
handy improvement for a future A-133-2 would be a switch to select  
negative/both/positive (or just both/positive only would be very  
nearly as useful).

Also a sum output, or normal the upper output to the lower output  
would be nice.

And normal +5V to the inputs so that the units can be used as offsets.

Martin

Sent from my iPhone

On 5 Feb 2015, at 07:54, "Neil Kagan blinkenlicht@yahoo.com  
[Doepfer_a100]" <Doepfer_a100@yahoogroups.com> wrote:
Show quoted textHide quoted text
> If it's like the A-133, I find the 'zero' point to be very small.  
> Same with the Polarizing mixer.
>
> Neil
>
> Sent from my iPhone
>
> On 5 Feb 2015, at 03:14, raulpena1974@yahoo.com [Doepfer_a100] <Doepfer_a100@yahoogroups.com 
> > wrote:
>
>>
>> Hello. I am doing a series on the A106-5. I read that the CV2 is a  
>> polarized input so around 12 o' clock the cv input is at zero, at  
>> +5 it is at fully positive input, and at -5 it is an inverted  
>> version of the cv input.
>>
>> As long as I understand this correctly, at zero I should have no cv  
>> but when I input an envelope it does affect the cutoff a slight  
>> amount.
>>
>> Can anyone confirm this behavior or explain if I am  
>> misunderstanding something?
>>
>>
>>
>> Thanks for any help.
>>
>>
>>
>> Raul
>>
>
>

Re: [Doepfer_a100] Doepfer A106-5 filter CV2 question

2015-02-05 by Neil Kagan

Yes!! Brilliant idea :)

Sent from my iPhone
Show quoted textHide quoted text
> On 5 Feb 2015, at 10:01, Martin Fay martin@martinfay.com [Doepfer_a100] <Doepfer_a100@yahoogroups.com> wrote:
> 
> Dieter, is the A-133 implemented with "back-to-back" VCAs? If so a handy improvement for a future A-133-2 would be a switch to select negative/both/positive (or just both/positive only would be very nearly as useful).
> 
> Also a sum output, or normal the upper output to the lower output would be nice.
> 
> And normal +5V to the inputs so that the units can be used as offsets.
> 
> Martin
> 
> Sent from my iPhone
> 
>> On 5 Feb 2015, at 07:54, "Neil Kagan blinkenlicht@yahoo.com [Doepfer_a100]" <Doepfer_a100@yahoogroups.com> wrote:
>> 
>>  
>> If it's like the A-133, I find the 'zero' point to be very small. Same with the Polarizing mixer.
>> 
>> Neil
>> 
>> Sent from my iPhone
>> 
>>> On 5 Feb 2015, at 03:14, raulpena1974@yahoo.com [Doepfer_a100] <Doepfer_a100@yahoogroups.com> wrote:
>>> 
>>>  
>>> Hello. I am doing a series on the A106-5. I read that the CV2 is a polarized input so around 12 o' clock the cv input is at zero, at +5 it is at fully positive input, and at -5 it is an inverted version of the cv input.
>>> 
>>> As long as I understand this correctly, at zero I should have no cv but when I input an envelope it does affect the cutoff a slight amount.
>>> 
>>> Can anyone confirm this behavior or explain if I am misunderstanding something?
>>> 
>>> 
>>> 
>>> Thanks for any help.
>>> 
>>> 
>>> 
>>> Raul
>>> 
> 
>

Re: [Doepfer_a100] Doepfer A106-5 filter CV2 question

2015-02-05 by achtung_999

I am always wondering why no center detent pots were used on the polarizers in Doepfer modules.
I know this is more expensive... but still...

Ernst
Show quoted textHide quoted text
On Thu, Feb 5, 2015 at 11:39 AM, Neil Kagan blinkenlicht@yahoo.com [Doepfer_a100] <Doepfer_a100@yahoogroups.com> wrote:

Yes!! Brilliant idea :)

Sent from my iPhone

On 5 Feb 2015, at 10:01, Martin Fay martin@martinfay.com [Doepfer_a100] <Doepfer_a100@yahoogroups.com> wrote:

Dieter, is the A-133 implemented with "back-to-back" VCAs? If so a handy improvement for a future A-133-2 would be a switch to select negative/both/positive (or just both/positive only would be very nearly as useful).

Also a sum output, or normal the upper output to the lower output would be nice.

And normal +5V to the inputs so that the units can be used as offsets.

Martin

Sent from my iPhone

On 5 Feb 2015, at 07:54, "Neil Kagan blinkenlicht@yahoo.com [Doepfer_a100]" <Doepfer_a100@yahoogroups.com> wrote:

If it's like the A-133, I find the 'zero' point to be very small. Same with the Polarizing mixer.

Neil

Sent from my iPhone

On 5 Feb 2015, at 03:14, raulpena1974@yahoo.com [Doepfer_a100] <Doepfer_a100@yahoogroups.com> wrote:

Hello. I am doing a series on the A106-5. I read that the CV2 is a polarized input so around 12 o' clock the cv input is at zero, at +5 it is at fully positive input, and at -5 it is an inverted version of the cv input.

As long as I understand this correctly, at zero I should have no cv but when I input an envelope it does affect the cutoff a slight amount.

Can anyone confirm this behavior or explain if I am misunderstanding something?


Thanks for any help.


Raul


AW: [Doepfer_a100] Doepfer A106-5 filter CV2 question

2015-02-05 by yahoo@doepfer.de

> I am always wondering why no center detent pots were used on the polarizers in Doepfer modules.
> I know this is more expensive... but still...
>
> Ernst

It has to do with technical problems. Our manufacturer is not able to manufacture a potentiometer with center detent AND mounting
bracket at the same time. In some modules potentiometers with center detents are used (e.g. A-188-2, A-138e) but these pots do not
have mounting brackets. Consequently such
potentiometers can be used only if the brackets are not necessary for the mechanical stability.

For the vertical type (as used in Dark Energy/Time and soem modules) another combo is not possible: center detent and thread. That's
why the filter type pot of the Dark Energy II is the only wobbly control because of the missing thread.

It's strange but unfortunately we have to accept these issues even if I don't really understand it. But it seems to be not that easy
as we were asking other manufacturers too. No other company was able so far to offer a pot with center detent AND bracket.

Best wishes
Dieter Doepfer

AW: [Doepfer_a100] Doepfer A106-5 filter CV2 question

2015-02-05 by yahoo@doepfer.de

> Dieter, is the A-133 implemented with "back-to-back" VCAs? If so a handy improvement for a future A-133-2 would be a
> switch to select negative/both/positive (or just both/positive only would be very nearly as useful).
>
>
> Also a sum output, or normal the upper output to the lower output would be nice.
>
>
> And normal +5V to the inputs so that the units can be used as offsets.
>
>
> Martin

Each sub-unit has only one VCA with amplification range 0-2 available. The polarizing function is simply realized by adding the
inverted signal to the VCA output, i.e. output = -input + v*input with v = 0-2 (VCA).

As we are about to redesign the A-133 with modern VCAs (2164). I will see which of the additional features will be included. We also
think about other function combos instead of dual modules (e.g. combo modules instead of dual ring modulator A-114, dual S&H A-148,
dual VC polarizer A-133, dual VC switch A-131 and so on ...). For some of these modules the dual function is not always meaningful
and other combos may make more sense. But before we begin this we have to finish the announced new modules.

Best wishes
Dieter Doepfer

Re: [Doepfer_a100] Doepfer A106-5 filter CV2 question

2015-02-05 by achtung_999

Thanks Dieter! That cleared up some questions I had for a while now.
Ernst
Show quoted textHide quoted text
On Thu, Feb 5, 2015 at 12:07 PM, yahoo@doepfer.de [Doepfer_a100] <Doepfer_a100@yahoogroups.com> wrote:
> I am always wondering why no center detent pots were used on the polarizers in Doepfer modules.
> I know this is more expensive... but still...
>
> Ernst

It has to do with technical problems. Our manufacturer is not able to manufacture a potentiometer with center detent AND mounting
bracket at the same time. In some modules potentiometers with center detents are used (e.g. A-188-2, A-138e) but these pots do not
have mounting brackets. Consequently such
potentiometers can be used only if the brackets are not necessary for the mechanical stability.

For the vertical type (as used in Dark Energy/Time and soem modules) another combo is not possible: center detent and thread. That's
why the filter type pot of the Dark Energy II is the only wobbly control because of the missing thread.

It's strange but unfortunately we have to accept these issues even if I don't really understand it. But it seems to be not that easy
as we were asking other manufacturers too. No other company was able so far to offer a pot with center detent AND bracket.

Best wishes
Dieter Doepfer



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Re: Doepfer A106-5 filter CV2 question

2015-02-05 by raulpena1974@yahoo.com

Ok. That makes more sense now.
It still makes for a useful function at CV2 and helps avoid external patching through a polarizer or inverter.
Thanks for the reply. I appreciate the help.

Regards.
Raul

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