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Re: [Doepfer_a100] Doepfer A106-5 filter CV2 question

2015-02-05 by Neil Kagan

Yes!! Brilliant idea :)

Sent from my iPhone

> On 5 Feb 2015, at 10:01, Martin Fay martin@martinfay.com [Doepfer_a100] <Doepfer_a100@yahoogroups.com> wrote:
> 
> Dieter, is the A-133 implemented with "back-to-back" VCAs? If so a handy improvement for a future A-133-2 would be a switch to select negative/both/positive (or just both/positive only would be very nearly as useful).
> 
> Also a sum output, or normal the upper output to the lower output would be nice.
> 
> And normal +5V to the inputs so that the units can be used as offsets.
> 
> Martin
> 
> Sent from my iPhone
> 
>> On 5 Feb 2015, at 07:54, "Neil Kagan blinkenlicht@yahoo.com [Doepfer_a100]" <Doepfer_a100@yahoogroups.com> wrote:
>> 
>>  
>> If it's like the A-133, I find the 'zero' point to be very small. Same with the Polarizing mixer.
>> 
>> Neil
>> 
>> Sent from my iPhone
>> 
>>> On 5 Feb 2015, at 03:14, raulpena1974@yahoo.com [Doepfer_a100] <Doepfer_a100@yahoogroups.com> wrote:
>>> 
>>>  
>>> Hello. I am doing a series on the A106-5. I read that the CV2 is a polarized input so around 12 o' clock the cv input is at zero, at +5 it is at fully positive input, and at -5 it is an inverted version of the cv input.
>>> 
>>> As long as I understand this correctly, at zero I should have no cv but when I input an envelope it does affect the cutoff a slight amount.
>>> 
>>> Can anyone confirm this behavior or explain if I am misunderstanding something?
>>> 
>>> 
>>> 
>>> Thanks for any help.
>>> 
>>> 
>>> 
>>> Raul
>>> 
> 
>

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