> the so called 'difference tone'. If you combine two sine waves f1 and > f2, that are far enough apart in frequency, you will be able to hear a > 'difference tone' f1 - f2. Does anybody on the list have enough > physics background to tell if this is basically the same thing going > on? Or is this something else? Or is it too off topic :) That's one of the basic principles of the frequency shifter. I have a word document that explains all the trigonometric formulas behind the RM/FS (sorry the words are in German). If anybody's interested I can send him the file (excerpt from the A-126 service manual). These are the most important formulas (a and b are the two inputs) 1. For RM only: · sin a x sin b = cos(a-b) - cos(a+b) or · cos a x cos b = cos(a-b) + cos(a+b) Sine and cosine have a phase shift of 90 degree (in other words: shifting a sine signal by 90 degrees leads to the cosine). But one cannot hear the difference between sine and cosine as long as no phase-fixed reference signal is available. Consequently you will hear the sum cos(a+b) and difference cos(a-b) in the RM output. As each audio signal can be treated as a sum of sine signals (Fourier analysis) any audio signals can be used. The multiplications (sin a x sin b and the same with cosine) are realized with the RM (four quadrant multiplier). 2. For additional frequency shifting: · sum of the above formulas: sina sinb + cosa cosb = 2 cos(a-b) · difference of the above formulas: sina sinb - cosa cosb = -2 cos(a+b) That's how in principle the frequency shifter works (2 RM for the sine and cosine and a simple adder and subtractor). For frequency shifting "b" is a sine/cosine oscillator (so-called quadrature oscillator) that generates sine and cosine simultaneously. "a" is the audio signal to be frequency-shifted. To obtain the cosine of this signal a so-called dome filter is required that generates a 90 degree phase shift of the signal over a wide frequency range (~ 60Hz - 12kHz for the A-126). This is because sine and cosine have a phase shift of 90 degree. I hope that's not too much mathematics for the weekend - but you have been asking .... Best wishes Dieter Doepfer
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AW: [Doepfer_a100] Re: comparing ring modulators
2005-11-18 by Dieter Doepfer
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