Re: hard science question
2008-07-02 by Doug
Off the top of my head, I don't think the set of square waves forms an orthogonal basis, so that a decomposition in terms of square waves is not unique. In other words, in the square wave basis, the "overtones" present are not unique. Not sure how you could apply a filter in this case, since the idea of a filter is to strip out members of the basis independently of the others. Beyond this I think our senses confirm the decomposition of vibrations in terms of sine waves, and this is simply a matter of experience agreeing with theory. I think if the ear were to experience a sound and we were expected to think about it in terms of the various contributions of square waves it would be difficult, because the contribution of each square wave in a particular sound is not unique. You could think about a sound being composed of two (or more) different sets of square waves, and the answer to the question would become ambiguous. Two or more, or many answers would be correct. In the case of sine waves, there is only one answer. Hopefully I am correct in this and not muddying the waters. Thanks, Doug --- In Doepfer_a100@yahoogroups.com, "Monroe Eskew" <monroe.eskew@...> wrote: > > I'm curious about harmonics. I've been looking for an explanation of why > different waveforms have different overtones. One explanation offered is in > terms of Fourier series. Every periodic function can be expressed as an > infinite sum of sine waves of increasing frequency and decreasing amplitude. > If we look at the Fourier series for a given curve (like a sawtooth or > square wave), then we can find the overtones by looking at the terms in the > sum. > > Now I like mathematics, but I'm not satisfied by this explanation. We can > express a function as a Fourier series, but we can also express it in other > ways. Perhaps a sine wave can be expressed as an infinite series of square > waves. Then a sine wave should have a lot of overtones. > > Here's my guess-- Qualitatively, different waveforms have different sounds, > and this does not necessarily need to be interpreted as having overtones. > However FILTERS are what truly reveal overtones. But the function of a > filter is determined by the fact that its resonant frequency is always a > sine wave. If we had square wave resonance, then we'd have totally > different filters, with the square wave being the least affected by the > filter. > > Is that more or less correct? > > Also, does the Fourier expression make the most sense to the human ear? > (i.e. Does the human ear have something akin to sine wave resonance?)
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> > Thanks, > Monroe > > > [Non-text portions of this message have been removed] >