[self-mocking on] Doh. Of course it is. I was just about to write that but I forgot about that inconvenient point where Y = 8/903.3 so I'm glad you cleared that up for us :) [self-mocking off] > formulas: > Y = 10 ^ (-d) > L = (Y^(1/3) * 116) - 16 for Y >= 8/903.3 > L = 903.3 * Y for Y < 8/903.3
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Re: [QuadtoneRIP] Re: Linearization Algorithm Anyone? (Cross Posted)
2006-01-28 by KevinG