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QTR-Quadtone RIP

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Message

Re: Understanding How Ink Density & Default Ink Limit Work

2011-01-27 by Terry

Mike,

Thanks for all of your help. 

Follow up to Q3

3) If you have the PK (or MK) ink set for 75 and a Second ink at 35 with
> the Default Ink Limit Blank, what is the total max density the printer
> produces? Is it 75 + 40 = 115?
>
No this is per channel so you have 75 for PK and 35 for the 2nd ink.
The max density depends on the relative ink densities of the two inks.

I'm using a R800 / R1800 standard Epson Inks and if my second ink is Blue in the above example (PK=75, Blue=40), how is the Relative Ink Density determined?

--- In QuadtoneRIP@yahoogroups.com, Michael King <drmrking@...> wrote:
>
> Terry,
> 
> The default is just that - it is used when there is no ink limit selected
> for that channel
> 
> So -
> 
> >  This is a basic question that I'm unclear about. I have used the Forum
> > Search feature and not come up with a clear answer.
> >
> > 1) If you have the PK (or MK) ink set for 75 and the default blank, does
> > that mean the PK prints at 75% of the maximum amount of ink the printer will
> > release?
> >
> Yes  for that PK channel.
> 
> > 2) If you have the PK (or MK) ink set for 75 and the Default Ink Limit at
> > say 50, what is the amount of ink the printer lays down?
> >
> 75
> 
> >
> > 3) If you have the PK (or MK) ink set for 75 and a Second ink at 35 with
> > the Default Ink Limit Blank, what is the total max density the printer
> > produces? Is it 75 + 40 = 115?
> >
> No this is per channel so you have 75 for PK and 35 for the 2nd ink.
> The max density depends on the relative ink densities of the two inks.
> 
> >
> > 4) If you have the PK (or MK) ink set for 75 and a second ink at 40 with
> > the Default Ink Limit at 90, what is the total max density the printer
> > produces?
> >
>  The max density depends on the relative ink densities of the two inks. as
> per question (3). Remember the default ink limit is ignored when you set an
> ink limit for a channel.
> 
> Mike
> 
> >
> > Thanks, Terry
> >
> >  
> >
> 
> 
> [Non-text portions of this message have been removed]
>

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