Analogue-sequencer

8 cv = pitch + 8 cv = velocity
8 gates

That's what I'd like.



--- In analogue-sequencer@yahoogroups.com, "Colin Fraser" <colin@...> wrote:
>
> Folks,
> 
> A quick poll...
> 
> If you had 24 pins on a connector free for signals (one has to be ground),
> how would you divide them up ?
> It could be, for example:
> 
> - 16 CVs, 8 gates
> - 12 CVs, 12 gates
> - 8 CV and 4 gate outs, 8 CV and 4 gate ins
> etc.
> 
> I'm leaning towards not having any gate inputs as such, since a CV input can
> be quantised to 1 bit if needed.
> Same applies to CV outputs, in most cases.
> So I guess it's more of a question of how many CV outputs to sacrifice for
> CV input ?
> 
> Best regards,
> Colin Fraser
> Sequentix Music Systems Ltd
> http://www.sequentix.com
>