At 11:06 PM 9/10/01 +1000, you wrote: >DbbBrook@... wrote: > >>Hi ya EVERY BODY. >> >>The equipment has been set up to compare the physical interactions of two >>sound waves at different freq.: Two generators (A+B) are fed to both an >>oscilloscope and a loud speaker via switch box enabling each to be viewed and >>heard either separately or combined. >> >> >>AMPLIFIER OSCILLOSCOPE A B >> [ [ [ \ / >> [ [ [_____________[ ] wall >> [ [_________________________________[ ] (suppose to be box) >> [__________________________// >> // >>( I tried to above to draw a diagram, to see if it would help any one better >>- I know not very good, but at least I tried) WEEEEE! Don't give up my >>studies for Art drawing HE HE >> >>DOES ANY ONE KNOW HOW TO WORK OUT THE CALCULATIONS FOR: >> >>The period output A as shown on the Oscillator is: 10 ms (milli seconds or >>metres per seconds)? >> >>The period output B as shown on Oscillator is: 0.1ms >> >>I need to calculate the output freq. for each tone generator and the >>resultant waveform of each sound wave at room temp? > >Output frquency in Hertz is the inverse of the period in Seconds. >F= 1/period, if period is 0.1 ms then F=1/0.0001 = 10,000 Hz or 10 KHz > >I can only imagine that you need to graph the pressure wave if you are >considering room temperature. I believe the velocity of sound is approx >320 Metres per second at 20 degrees C (no idea in imperial) in air. >You may need to find a more accurate figure. In any case, Wavelength in >Metres is equal to velocity/period. I think you'll find that 340 m/sec is closer to the mark which is roughly 1100 feet per second. Just divide those disances (340M or 1100 feet) by the frequency to get the wavelength of an audio wave of frequency (f). Frequency = 1/period >0.1 ms I think is 0.010s? I know anything with nought on left from decimal >point. Oh I'm getting confused. Does any one know how to do this calculation? >If so can you explain it to me. No. 1 ms = 1 millisec which is one thousandth of a second = 0.001 second So 0.1 msec is 0.0001 second. Regards, Murray
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Re: [L-OT] RE:of topic - ACOUSTICS AGAIN
2001-10-09 by Murray McDowall
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