Lpc2000

* Marko Pavlin <mp@...>:
> >  How can I call function where address is in
> >  pointer? Something like this:
> >
> > void test1(void){
> >    puts("blah");
> > }
> >
> >
> > void *exec;
> >
> > void main(void) {
> >     exec = (void *)test1;
> >     __asm
> >     {
> >           BL             exec
> >     }

You need to declare exec as a function pointer.
Then you can assign it the address of any function
with the same prototype and call it like any other
function:

void test1(void){
   puts("blah");
}

void (*exec)(void); // Declare as function pointer.

void main(void) {
    exec = test1;
    exec();
}

* Jim Parziale <nuncio.bitis@...>:
> After setting:
>     exec = (void *)test1;
> Just call via exec:
>      exec();
> 

exec must be declared as a function pointer,
otherwise the compiler won't know how to set up
the parameters and pick up the return value for
the function (even if there are none in this
case.)

-- 
JR