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Lpc2000

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Message

Re: AD0 not working properly - help

2006-03-03 by Sutton Mehaffey

Richard,

I had these set up in an init file that I didn't include with the code.

Also, it didn't matter if I did the write to AD0CR all at once or
separate.  No change in the data.

I couldn't find anything in the errata sheet.  I printed out Errata
1.2 released on 2/27.  Where is the errata you were referring to?

Sutton


IODIR0 &= 0x8FFFFFFF;   // AD0 (P0.28, P0.29, P0.30) defined as inputs
PCONP |= 0x00001000;    // Enable AD0
PINSEL1 |= 0x15000000;  // AD0.1, AD0.2, AD0.3 all defined

AD0CR = 0x01200404;

// AD0CR |= 0x00200000;  // turn on AD0
// AD0CR |= 0x00000400;  // divide 12Mhz clock by 3 (max 4.5Mhz ADC clk)
// AD0CR |= 0x00000004;  // select channel AD0.2
// AD0CR |= 0x01000000;  // start conversion now

while ((AD0STAT & 0x00000004) == 0);  // DONE2 status bit in AD0STAT
result = (AD0DR2 & 0x0000FFC0) >> 6;  // bits 6-15 are result (0-2055)


 

--- In lpc2000@yahoogroups.com, Richard Duits <yahoo@...> wrote:
>
> You should start the AD conversion with a single write and not a series 
> of read-modify-write operations.
> 
> Also make sure that none of the ADC capable pins stay below 3.3 Volt 
> even if they are not used as ADC inputs (see errata for more info).
> 
> Make sure you configure the pin as ADC input with the pin configuration 
> registers.
> 
> Regards,
> Richard.
> 
> 
> 
> 
> Sutton Mehaffey wrote:
> > Please help us to improve Yahoo! Groups. Take the survey now! 
> > <http://v2.decipherinc.com/survey/yahoo/yah05014?list=18>
> > I am trying to read a battery voltage (~12V) on AD0 channel 2.  I have
> > a breadboard circuit with a voltage divider that is working properly
> > that gives a reading between 1.8V and 2.3V more or less.  I am using a
> > variable power supply to generate these voltages.
> >
> > When I connect the 1.8-2.3V to P0.29 (AD0.2), I read CFF (all 10 bits
> > high) no matter what.  Can someone tell by the code below if I have a
> > setting wrong?  My PCLK is 12Mhz.
> >
> >
> > AD0CR |= 0x00200000;  // turn on AD0
> > AD0CR |= 0x00000400;  // divide 12Mhz clock by 3 (max 4.5Mhz ADC clk)
> > AD0CR |= 0x00000004;  // select channel AD0.2
> > AD0CR |= 0x01000000;  // start conversion now
> >
> > while ((AD0STAT & 0x00000004) == 0);   // DONE2 status bit in AD0STAT
> > result = (AD0DR2 & 0x0000FFC0) >> 6;   // bits 6-15 are result
(0-2055)
> >
> > DONE2 is set, and result is always CFF.
> >
> > Sutton - dodge1955
>

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