Lpc2000

Andrew, thank you very much ;) In fact I am working with CrossWorks but  I coudn't trigger any interrupt there, so I thought, maybe I will do it  in Keil. But it didn't work either. Now it is working ;) It helped me  much, thanks again ;)

Grodo Grodo <grodo2k@...> wrote:          Thank you, I'll try it and say if it works by me.
  
  Andrew Berney <amb@...> wrote:          Hi,
    
    we could do with the function UART0_init from your code, however I suspect
    your problem is that you're not reading U0IIR to clear the UART IRQ. You
    also have a huge delay inside your IRQ which kind of defeats the point of
    using it. Have a look at the description of U0IIR register.
    
    Here is a working example from a 2129 which should work equally well on your
    chip with minor modification:
    
    void main(void)
    {
      // init the serial ports
      init_serial();
    
      // main loop
      while(1)
      {
        for(;;);
      }
    }
    
    void init_serial (void)          // Initialize Serial Interface
      {
    
      //UART0
      VPBDIV  = 0x00000001;          //Set PClk to 60Mhz
      PINSEL0 = 0x00000005;     //Enable TxD0, RxD0
    
      U0LCR   = 0x00000083;     //8 bits, no Parity, 1 Stop bit
      U0DLL   = 0x00000084;     // 9600 Baud Rate @ 60MHz VPB Clock
      U0DLM   = 0x00000001;
      U0LCR   = 0x00000003;     // DLAB = 0
      U0IER   = 0x00000001;     //enable rx data available interrupt
    
      VICVectCntl1 = 0x00000026;
      VICVectAddr1 = (unsigned)uart0_irq;
      VICIntEnable |= 0x00000040;
    
      U0FCR   =  0x00000001;              //Enable FIFO & trigger level to 1  bytes
    }
    
    static unsigned int U0IIR_copy;
    
    void uart0_irq(void) __irq
    {
      //check for a character from the UART0 RX FIFO
      if((U0LSR & 0x01) == 0x01)  //if there is a character
      {
         toggle_LED(1);             //do this to suit your board
      }
    
      //exit ISR
      U0IIR_copy = U0IIR;
      VICVectAddr = 0x00000000;       //dummy write to re-enable interrupt for next
    time
    }
    
    
    
    -----Original Message-----
    From: lpc2000@yahoogroups.com [mailto:lpc2000@yahoogroups.com]On Behalf
    Of grodo2k
    Sent: 21 March 2006 11:38
    To: lpc2000@yahoogroups.com
    Subject: [lpc2000] interrupts + Keil + LPC2294
    
    
    Hello
    could someone be so kind and say, what is wrong in following code? Or
    maybe it is ok, but it doesn't work... I want trigger an interrupt
    using UART0. I am using Keil. (UART0 is ok, it sends a string from tab).
    
    thanks in advance
    
    int i,j;
    char tab[] = "UART0 is working properly";
    
    void UART0INT() __irq
    {
          IO0CLR |= 0x20000;  //clr P0.17 (it's a LED)
          for(i=0;i<5;i++)
          {
                for(j=0;j<50000;j++){}
          }
          send_char_u0('A');
          VICVectAddr = 0x00000000; //dummy write
    }
    
    int main(void)
    {
          PLL_ON();
          LED_init();
          VPBDIV = 0x1;
          UART0_init();
          IO0SET |= 0x20000;  //set P0.17
          send_string_u0(tab);
          VICIntSelect = 0x00000000;
          VICVectAddr0 = (unsigned) UART0INT;
          VICVectCntl0  = 0x26;      //UART0
          VICIntEnable =  0x40;             //bit 6 = UART0
          while(1)
          {
    
          }
    
          return 0;
    
    }
    
    
    
    
    
    
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