>Well considering the 2103 claims a typical operating current on the 1V8 supply of from 7mA to 41mA you are already in a different league. Three orders of magnitude is not easily crossed. Not necissarially - the AtMega128 8-bit Avr sucks a healthy 10mA when operating at 8MHz. I did the calculations and when a mote is operating (sample sensors, tx data) for 10mS every 60s, you have a 6000:1 duty cycle, so your 10mA looks like 1.6uA. Therefore the sleep current is the dominant drain on your batteries. TI's vey best LDO's eat 10uA Iq, so you're looking at two LDO's doubling your dominant current consumption. Can take a mote's effective deployed life down accordingly. As people mentioned, having as much board eaten by regulators as the processor is quite anoying as well. I suppose the ideal solution is a discrete watchdog chip which would pull up the power supplies on interrupt long enough for the chip to boot. Adds yet more mm-sq to your design, and I doubt very much I can find one of those to run at 10uA. Well, I'm out. Maybe Philips will take notice and let VccIO go down to 1.8Von their next effort. I think it's silly to run a 3.3V rail to get a 1.8V core processor to talk to a 1.8V core FPGA which is another thing I do.... Steve [Non-text portions of this message have been removed]
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Re: Re: Re: 2103 forces dual supply?
2006-04-26 by Steve Franks
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