It sounds like your inputs aren't truly differential. You've referenced the V- input as a reference 90mV.... which makes it a unipolar signal, essentially. A differential input won't have this type of reference as Karem mentioned below. You could force the inputs into the 0-5V range by using a 2.5V ADC reference. You can still you a differential input but will then want to make the input amplifier's common mode reference at 2.5V... or half of the reference voltage so that it's centered in the range. Edwin --- In lpc2000@yahoogroups.com, "Leighton Rowe" <leightonsrowe@y...> wrote: > The analog inputs and references look stable to me. No floating > pins. I've made the Vin- input closer to ground: > > Analog input (always +ve)---> Vin+ > 0V ---> Vin- > 3V ---> Vref > 5V ---> AVDD/DVDD > > ...but the same readings are still coming out. Maybe it's because > I'm using a "true differential" ADC. I heard the setup's different > compared to pseudo differential which I'm more accustomed to using. > > --- In lpc2000@yahoogroups.com, "Kerem Or" <k.or@s...> wrote: > > It appears there is a common mode voltage problem. Check if there > is a > > current return path between AIN-/AIN+ and AGND. What you observed > can happen > > if the signal source is floating with respect to AGND. As you have > noted the > > AD accepts -2.5V to 2.5V. But since the part is not bipolar, the > applied > > input signal must not be above VCC or below ground with respect to > AGND. > > i.e, -2.5V actually means 0V connected to AIN+ and 2.5V connected > to AIN-. > > It is not -2.5V with respect to AGND. > > > > Just make sure voltage on any of the differential pins is in > between the > > part's common mode range. > > > > Kerem
Message
Re: Using External AD Converters
2004-09-17 by ebland_us
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