Lpc2000

Hi folks,

I'm struggling to understand how to handle interrupts for the 2294. I can see 
that when I get an interrupt, the processor jumps off to the following line 
of code in the startup assembly file:

  ldr pc, [pc, #irq_handler_address - . - 8]

This then jumps off to the following line of code:

irq_handler:
  b irq_handler

There is a comment that these are defined as weak variables and can be 
redefined in user code. So, at the moment, it's quite easy to see that when 
there's an interrupt the program just gets stuck on this line of code. It 
seems obvious that I then have to redirect this code to the appropriate  
interrupt handler. I would have thought that I need to read the  VICVectAddr 
which should contain the address of one of the registers VICVectAddr0 to 
VICVectAddr15. I assume that the program would jump to that VICVectAddrX 
register and then from there to the user code which has been written to deal 
with the interrupt.

What I'm not clear about is how to replace this line of code:

irq_handler:
  b irq_handler

To something like:

irq_handler:
  b (VICVectAddr)

In other words, when I get to the line of code 

irq_handler:

Then jump to the location pointed to be the contents of VICVectAddr. I assume 
that if I can set that up, the compiler will sorted out jumping to wherever 
VICVectAddrX points to.

Am I basically correct in my assumptions, or way off line?! 

Many thanks,

Rob