Lpc2000

--- In lpc2000@yahoogroups.com, "alexmotin" <alexmotin@y...> wrote:
> Hello.
> 
> I have a big problem!
> 
> I use IAR 4.10B LPC2119 and i want to use IRQ UART1
> I did it so:
> 
> 
> 
>   InstallHandler((unsigned int *)0x18, (unsigned int)
> IRQ_ISR_Handler);
>   VICIntEnable |= 0x80; 
>   U1IER = 0x01;        
>   __enable_interrupt();
> 
> where 
> 
> unsigned int InstallHandler(unsigned int *vector, unsigned int 
> function)
> {
>   unsigned int vec, old_vec;
> 
>   vec = ((function - (unsigned int)vector - 8) >> 2);
> 
>   old_vec = *vector;
>   vec |= 0xEA000000; /* add opcode for B instruction */
>   *vector = vec;
> 
>   old_vec &= ~0xEA000000;
>   old_vec = ( old_vec << 2 ) + (unsigned int)vector + 8;
>   
>   return(old_vec);
> }
> 
> 
> 
> I have try a lot of kind to do it. But ARM always jump to 0x14 when 
> happend interrupt.
> 
> If anybody know what to do, tell me please.
> 
> It will be very big hppy for me? becouase i have try to do it ll 
> week.

Had the same issue a little while ago (new at this ARM stuff also).  
The interrupt handler install function is only if you are running 
your interrupt vector table from RAM.  So either adjust your MEMMAP 
to reflect this or run the vector table from Flash.  If running from 
flash just place the following line before the interrupt service 
routine:

#pragma vector = 0x18

Has worked for me so far although I am having other issues with IAR 
(or setup).