IRQ - I don't know what me do. HELP!!! PLZ
2005-07-24 by alexmotin
Hello.
I have a big problem!
I use IAR 4.10B LPC2119 and i want to use IRQ UART1
I did it so:
InstallHandler((unsigned int *)0x18, (unsigned int)
IRQ_ISR_Handler);
VICIntEnable |= 0x80;
U1IER = 0x01;
__enable_interrupt();
where
unsigned int InstallHandler(unsigned int *vector, unsigned int
function)
{
unsigned int vec, old_vec;
vec = ((function - (unsigned int)vector - 8) >> 2);
old_vec = *vector;
vec |= 0xEA000000; /* add opcode for B instruction */
*vector = vec;
old_vec &= ~0xEA000000;
old_vec = ( old_vec << 2 ) + (unsigned int)vector + 8;
return(old_vec);
}
I have try a lot of kind to do it. But ARM always jump to 0x14 when
happend interrupt.
If anybody know what to do, tell me please.
It will be very big hppy for me? becouase i have try to do it ll
week.