You have a couple of faults:
In Interruption: VicVectAddr = 0; (Not 0xff)
In main, include:
VicIntEnable = 0x10; // Enable timer 0 interrupt
Regards
--- In lpc2000@yahoogroups.com, "DECwiz \(Fred van Kempen\)"
<decwiz@y...> wrote:
> In the ISR, you need to reset the VIC using 0x00, not ff:
>
> VICVectAddr = 0;
>
> will work.
>
> Also, in main:
>
> VICIntSelect=0x00000000; //assigne interrupt timer 0 til type
IRQ
>
> will not work.. you need to SET the bit for the specific VIC
channel, such as:
>
> VICIntSelect |= (1 << VIC_TIMER0);
>
> or alike.
>
> --fred
>
>
> boje_d <boje_demant@h...> wrote:
> Hi im trying to make the interrupt work om a lpc2294. I am using
> timer 0 and see the interrupt being enabled (test routine on
display)
> but the interrupt does NOT activate the interrupt routine. Ill put
in
> some code so maybe someone can see my error??? And give a little
> help ??
>
> than you (i hope)
>
> Best regards
> Boje Demant
>
> interrupt routine
> static void Timer0Interrupt(void) __attribute__ ((interrupt
("IRQ")));
> static void Timer0Interrupt(void){
> // (*timer_function)(); // Call timer callback function.
> //
> // T0_TCR=0; //stop timer
> // T0_TCR=2; //Reset timer
> // T0_TCR=1; //start timer
> LIGHT_LCD_ON;
> T0_IR = 0xff; // Clear timer 0 interrupt line.
> VICVectAddr=0xff;
> }
>
>
>
>
> in main:
>
> T0_PR=58982; //setup prescaler = 1msek
> T0_TCR=0x00000002; //Reset timer
> T0_MR0= 1500; //2 (2 sek for interrupt;
> T0_MCR=0x00000003; //generate interrupt on match
> VICProtection=0; //
> VICIntEnClear=0xffffffff; //disable all interrupts
> VICSoftIntClear=0xffffffff;
> VICDefVectAddr=(unsigned long)&DefInterrupt;
> VICIntSelect=0x00000000; //assigne interrupt timer 0 til type
IRQ
> VICVectAddr0= (unsigned long)&Timer0Interrupt; //opsæt vector
> VICVectCntl0= 0x00000024; //enable vector iterrupt
>
>
>
>
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Re: Olimex lpc e2294 board interrupt help - GNU C
2005-07-28 by Angel Sanchez
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