Lpc2000

PINSEL2 = (PINSEL2 & (0 << 2) & (0 << 3));

According to this, you're clearing PINSEL2 altogether. Did you mean:

PINSEL2 = (PINSEL2 & (1 << 2) & (1 << 3));

On 8/2/05, soren_t_hansen <soren_t_hansen@...> wrote:
> 
>  --- In lpc2000@yahoogroups.com, "Aalt Lokhorst" <lokhorst@s...> wrote:
> > Hello Søren,
> > 
> > Not sure what processor you are using but I think you are diabling
> the JTAG by changing a JTAG line into a GPIO line.
> > 
> > I am using the LC2129 and the usermanual of this processor shows the
> following:
> > 
> > Table 63: Pin Function Select Register 2 for LPC2119/2129/2194
> > (PINSEL2 - 0xE002C014)
> > 
> > 1:0 Reserved.
> > 
> > 2 When 0, pins P1.36:26 are used as GPIO pins.
> > When 1, P1.31:26 are used as a Debug port. (RTCK)
> > 
> > 3 When 0, pins P1.25:16 are used as GPIO pins.
> > When 1, P1.25:16 are used as a Trace port. (TRACESYNC)
> > 
> > 4:5 Reserved. Note: These bits must not be altered at any time.
> > Changing them may result in an incorrect code execution.
> > 
> > 6:31 Reserved.
> > 
> > According to this info you are disabling the JTAG RTCK line.
> > 
> > Hope this helps,
> > Aalt
> > 
> 
> Ups forgot to tell - it's a lpc2132 :o)
> 
> I use the following line and it still crashes:
> 
> PINSEL2 = (PINSEL2 & (0 << 2) & (0 << 3));
> 
> At the moment it isn't that big a deal, since the PINSEL2 bit 2 and 3
> are 0 at reset, and that's what I want them to be. It just pusled me
> that I couldn't write to those two bits whithout the MCU crashing.
> 
> /Søren
>


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