Actually, it's *2* keys, because a chorused voice with a 12th order filter uses 4 voices, not 3. "2 voices" x "2 12th order penalty" x "4 layers" x "3 linked" = 48 voices per note! And no, they can't share the filter because one osc is panned left and the other right, thus needing separate filter paths to keep the signals separate. -Aaron --- erik_magrini@... wrote: > > I mean 4 keys, math was never my strong point :) > > Link three of these presets > together and you can only press 3 keys before running out of poly. > :) > > > A chorused layer takes up twice the polyphony, because it utilises > two detuned oscillators. > A layer with 12-order filter takes up twice the polyphony. > So, a chorused layer with 12-order filter takes up 4 times the > polyphony? This always has been obvious for me, but yesterday I > thought that maybe, somehow the two oscillators are able to share the > filter? > Sorry if it's a stupid question, I just want to make sure. __________________________________ Do you Yahoo!? Yahoo! Mail - 250MB free storage. Do more. Manage less. http://info.mail.yahoo.com/mail_250
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Re: [xl7] polyphony question
2004-12-16 by Aaron Eppolito
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